Lenguaje

InOutArgument<T>.FromExpression Método

Definición

Inicializa y devuelve un nuevo InOutArgument<T> construido mediante el especificado Activity<TResult>.

public:
 static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.InOutArgument<T> FromExpression(System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)

Parámetros

expression
Activity<Location<T>>

Valor del argumento.

Devoluciones

Nuevo argumento.

Se aplica a