Font.Equals(Object) 方法
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
表示指定的物件是否為 ,Font且具有與此FontFamily相同的 GdiVerticalFont、 GdiCharSet、 Style、 SizeUnitFont 、 及 屬性值。
public:
override bool Equals(System::Object ^ obj);
public override bool Equals(object? obj);
public override bool Equals(object obj);
override this.Equals : obj -> bool
Public Overrides Function Equals (obj As Object) As Boolean
參數
- obj
- Object
要測試的對象。
傳回
true若obj參數為 aFont,且具有相同的 FontFamily、 GdiVerticalFont、 GdiCharSet、 StyleSize、 、 Unit 及 性質值Font;否則, false。
範例
以下程式碼範例是為 Windows Forms 設計的,並需要 PaintEventArgse,這是 Paint 事件處理程序的參數。 程式碼會創建兩個 Font 物件,然後測試它們是否等價。
public:
void Equals_Example( PaintEventArgs^ /*e*/ )
{
// Create a Font object.
System::Drawing::Font^ firstFont = gcnew System::Drawing::Font( "Arial",16 );
// Create a second Font object.
System::Drawing::Font^ secondFont = gcnew System::Drawing::Font( gcnew FontFamily( "Arial" ),16 );
// Test to see if firstFont is identical to secondFont.
bool fontTest = firstFont->Equals( secondFont );
// Display a message box with the result of the test.
MessageBox::Show( fontTest.ToString() );
}
public void Equals_Example(PaintEventArgs e)
{
// Create a Font object.
Font firstFont = new Font("Arial", 16);
// Create a second Font object.
Font secondFont = new Font(new FontFamily("Arial"), 16);
// Test to see if firstFont is identical to secondFont.
bool fontTest = firstFont.Equals(secondFont);
// Display a message box with the result of the test.
MessageBox.Show(fontTest.ToString());
}
Public Sub Equals_Example(ByVal e As PaintEventArgs)
' Create a Font object.
Dim firstFont As New Font("Arial", 16)
' Create a second Font object.
Dim secondFont As New Font(New FontFamily("Arial"), 16)
' Test to see if firstFont is identical to secondFont.
Dim fontTest As Boolean = firstFont.Equals(secondFont)
' Display a message box with the result of the test.
MessageBox.Show(fontTest.ToString())
End Sub