Tuple<T1,T2,T3,T4,T5>(T1, T2, T3, T4, T5) 建構函式
定義
重要
部分資訊涉及發行前產品，在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊，不做任何明確或隱含的瑕疵擔保。
初始化 Tuple<T1,T2,T3,T4,T5> 類別的新執行個體。
public:
Tuple(T1 item1, T2 item2, T3 item3, T4 item4, T5 item5);public Tuple(T1 item1, T2 item2, T3 item3, T4 item4, T5 item5);new Tuple<'T1, 'T2, 'T3, 'T4, 'T5> : 'T1 * 'T2 * 'T3 * 'T4 * 'T5 -> Tuple<'T1, 'T2, 'T3, 'T4, 'T5>Public Sub New (item1 As T1, item2 As T2, item3 As T3, item4 As T4, item5 As T5)參數
- item1
- T1
元組的第一個組件值。
- item2
- T2
元組第二成分的值。
- item3
- T3
該元組第三個成分的值。
- item4
- T4
元組第四個成分的值。
- item5
- T5
元組第五分量的值。
備註
你也可以用靜態 Tuple.Create<T1,T2,T3,T4,T5>(T1, T2, T3, T4, T5) 方法實例化一個五元組物件，而不必明確指定其組件的類型。 以下範例使用此 Tuple.Create<T1,T2,T3,T4,T5>(T1, T2, T3, T4, T5) 方法實例化一個 5 元組，其第一成分為型別 String ，其餘四個成分為型別 Int32。
var tuple5 = Tuple.Create("New York", 1990, 7322564, 2000, 8008278);
Console.WriteLine("{0}: {1:N0} in {2}, {3:N0} in {4}",
tuple5.Item1, tuple5.Item3, tuple5.Item2,
tuple5.Item5, tuple5.Item4);
// Displays New York: 7,322,564 in 1990, 8,008,278 in 2000
let tuple5 =
Tuple.Create("New York", 1990, 7322564, 2000, 8008278)
printfn $"{tuple5.Item1}: {tuple5.Item3:N0} in {tuple5.Item2}, {tuple5.Item5:N0} in {tuple5.Item4}"
// Displays New York: 7,322,564 in 1990, 8,008,278 in 2000
Dim tuple5 = Tuple.Create("New York", 1990, 7322564, 2000,
8008278)
Console.WriteLine("{0}: {1:N0} in {2}, {3:N0} in {4}",
tuple5.Item1, tuple5.Item3, tuple5.Item2,
tuple5.Item5, tuple5.Item4)
' Displays New York: 7,322,564 in 1990, 8,008,278 in 2000
這等同於以下對 Tuple<T1,T2,T3,T4,T5> 類別建構器的呼叫。
var tuple5 = new Tuple<string, int, int, int, int>
("New York", 1990, 7322564, 2000, 8008278);
Console.WriteLine("{0}: {1:N0} in {2}, {3:N0} in {4}",
tuple5.Item1, tuple5.Item3, tuple5.Item2,
tuple5.Item5, tuple5.Item4);
// Displays New York: 7,322,564 in 1990, 8,008,278 in 2000
let tuple5 =
Tuple<string, int, int, int, int>("New York", 1990, 7322564, 2000, 8008278)
printfn $"{tuple5.Item1}: {tuple5.Item3:N0} in {tuple5.Item2}, {tuple5.Item5:N0} in {tuple5.Item4}"
// Displays New York: 7,322,564 in 1990, 8,008,278 in 2000
Dim tuple5 = New Tuple(Of String, Integer, Integer,
Integer, Integer) _
("New York", 1990, 7322564, 2000, 8008278)
Console.WriteLine("{0}: {1:N0} in {2}, {3:N0} in {4}",
tuple5.Item1, tuple5.Item3, tuple5.Item2,
tuple5.Item5, tuple5.Item4)
' Displays New York: 7,322,564 in 1990, 8,008,278 in 2000
